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print the sum of all odd numbers from 1 to n:



print the sum of all odd numbers from 1 to n:

Sum of the Digits

In mathematics, the digit sum of a given integer is the sum of all its digits (e.g. the digit sum of 84001 is calculated as 8+4+0+0+1 = 13)
Odd Number

An odd number is an integer which is not a multiple of two. If it is divided by two the result is a fraction. One is the first odd positive number. The next four bigger odd numbers are three, five, seven, and nine. So some sequential odd numbers are: {1,3,5,7,9,11,13,15,17,19,21,23,25. And then you add all the number up if its over 1,000 its odd if under 1,000 its even..}

#include <iostream>
#include<conio.h>
#include<stdlib.h>

using namespace std;

int main() {
   // Declare Variables
   int i, limit, sum = 0;

   cout << "Simple C++ Program : print the sum of all odd numbers from 1 to n\n";
   cout << "\nEnter Limit : ";
   cin>>limit;

   for (i = 1; i <= limit; i += 2) {
      sum += i;
      cout << "\nOdd Number Is : " << i << " Sum : " << sum;
   }

   cout << "\n\nTotal Sum of Odd numbers 1 to " << limit << " : " << sum;

   getch();
   return (0);
}

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