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C++ > If Else and Switch Case Code Examples

Check Leap Year or Not



Check Leap Year or Not

To check whether the input year is a leap year or not a leap year in C++ Programming, you have to ask to the user to enter the year and start checking for the leap year. To check that the year is a leap year or not, following these rules:

    If year is divided by 4 but not by 100, then it is a leap year.
    If year is divided by 100, then it is not a leap year.
    If year is divided by 400, then it is a leap year.
    And in all other cases, it is not a leap year.

Following C++ program ask to the user to enter the year to check whether it is a leap year or not, then display it on the screen:

/* C++ Program - Check Leap Year or Not */
		
#include<iostream.h>
#include<conio.h>
void main()
{
	clrscr();
	int yr;
	cout<<"Enter year :";
	cin>>yr;
	if((yr%4==0) && (yr%100!=0))
	{
		cout<<"This is a Leap Year";
	}
	else if(yr%100==0)
	{
		cout<<"This is not a Leap Year";
	}
	else if(yr%400==0)
	{
		cout<<"This is a Leap Year";
	}
	else
	{
		cout<<"This is not a Leap Year";
	}
	getch();
}

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