C++ Programming Code Examples C++ > If Else and Switch Case Code Examples Odd Or Even Program Using Functions Odd Or Even Program Using Functions A formal definition of an even number is that it is an integer of the form n = 2k, where k is an integer;[3] it can then be shown that an odd number is an integer of the form n = 2k + 1. /*## Odd Or Even Example Program Using Functions In C++*/ #include <iostream> #include<conio.h> #include<stdlib.h> using namespace std; string odd_even(int i); int main() { // Declare Variables int number; cout << "Simple C++ Program : Odd Or Even Example Program Using Functions\n"; //Read Value cout << "\nEnter an integer : "; cin>>number; //Call Function and Print Result cout << "\n\nResult : " << odd_even(number); getch(); return (0); } string odd_even(int number) { if (number % 2 == 0) { return "your number is even number"; } else { return "your number is odd number"; } }
