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C++ > Mathematics Code Examples

Check the Number is Armstrong or Not



Check the Number is Armstrong or Not

To check whether a number is an Armstrong number or not an Armstrong number in C++ programming, you have to ask to the user to enter the number (any positive number), now check for the Armstrong number i.e., whether the entered/given number is an Armstrong number or not.

To check whether any positive number is an Armstrong number or not, following is the example:

    Since 153 is equal to 1*1*1 + 5*5*5 + 3*3*3. So 153 is an Armstrong number
    Since 12 is not equal to 1*1*1 + 2*2*2. So 12 is not an Armstrong number

Following C++ program ask to the user to enter any positive integer to find whether it is an Armstrong number or not, then display the result on the screen:
		
#include<iostream.h>
#include<conio.h>
void main()
{
	clrscr();
	int n, nu, num=0, rem;
	cout<<"Enter any positive number : ";
	cin>>n;
	nu=n;
	while(nu!=0)
	{
		rem=nu%10;
		num=num + rem*rem*rem;
		nu=nu/10;
	}
	if(num==n)
	{
		cout<<"Armstrong Number";
	}
	else
	{
		cout<<"Not Armstrong Number";
	}
	getch();
}

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